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A farmer has 264 feet of fencing and wants to build two identical pens for his prize-winning pigs. The pens will be arranged as shown. Determine the dimensions of a pen that will maximize its area.
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P = 4y + 3x = 264ft 3x = 264 - 4y x = 88 - (4y/3) A = 2*x*y Optimization problem: Insert x of perimeter into area formula: A = 2*(88-(4y/3))*y A = 176y - (8y^2 / 3) Take derivative of area: A' = 176 - (48y/9) Set A' to equal zero as to find the critical point. 0 = 176 - (48y/9) 48y/9 = 176 48y = 1584 y = 33 P = 4y + 3x = 264 264 = 4*33 + 3x 132 = 3x x = 44 Therefore the dimensions are x = 44 and y = 33.
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