Find the slope of the curve.
\[\frac{ 1 }{ x-1 }\] at x=2
I think you're teaching me... try setting it up just like you did last time... that seemed to work!
lim h->0 \[\frac{ \frac{ 1 }{ (a+h)-1 }-1 }{ h }\]
next?
im stuck lol
common denominator on the top stuff...
oooooo thx
you always need to be watching for ways to cancel that h on the bottom... can't have a 0 in the denominator when you do the limit.
ik 1 sec
\[\frac{ \frac{ 1 }{ a+h }-\frac{ a+h }{ a+h } }{ h }\]
\[\frac{ 1-a+h }{ a+h } (\frac{ 1 }{ h })\]
screwed up the top -a+h should be -(a+h)
\[\frac{ 1-(a+h) }{ h(a+h) }\]
now should i plug in 2 for a?
I think that's how you did it last time...
\[\frac{ -1-h }{ h(2+h) }\]
now i cant do anything but plug in the limit and as of now it doesnt exist.... i screwed up somewhere
possibly :( sorry... These are a bit of a pain...
ik haha n the sad part is this is my homework so it SHOULD be eaasy...
you lost me when you did the common denominator on top... either you simplified before you posted it, or you made an error there.
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