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Mathematics 16 Online
OpenStudy (anonymous):

Find the slope of the curve.

OpenStudy (anonymous):

\[\frac{ 1 }{ x-1 }\] at x=2

OpenStudy (anonymous):

I think you're teaching me... try setting it up just like you did last time... that seemed to work!

OpenStudy (anonymous):

lim h->0 \[\frac{ \frac{ 1 }{ (a+h)-1 }-1 }{ h }\]

OpenStudy (anonymous):

next?

OpenStudy (anonymous):

im stuck lol

OpenStudy (anonymous):

common denominator on the top stuff...

OpenStudy (anonymous):

oooooo thx

OpenStudy (anonymous):

you always need to be watching for ways to cancel that h on the bottom... can't have a 0 in the denominator when you do the limit.

OpenStudy (anonymous):

ik 1 sec

OpenStudy (anonymous):

\[\frac{ \frac{ 1 }{ a+h }-\frac{ a+h }{ a+h } }{ h }\]

OpenStudy (anonymous):

\[\frac{ 1-a+h }{ a+h } (\frac{ 1 }{ h })\]

OpenStudy (anonymous):

screwed up the top -a+h should be -(a+h)

OpenStudy (anonymous):

\[\frac{ 1-(a+h) }{ h(a+h) }\]

OpenStudy (anonymous):

now should i plug in 2 for a?

OpenStudy (anonymous):

I think that's how you did it last time...

OpenStudy (anonymous):

\[\frac{ -1-h }{ h(2+h) }\]

OpenStudy (anonymous):

now i cant do anything but plug in the limit and as of now it doesnt exist.... i screwed up somewhere

OpenStudy (anonymous):

possibly :( sorry... These are a bit of a pain...

OpenStudy (anonymous):

ik haha n the sad part is this is my homework so it SHOULD be eaasy...

OpenStudy (anonymous):

you lost me when you did the common denominator on top... either you simplified before you posted it, or you made an error there.

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