Question

Square root of a rational function

Answer 1

\[\v_0=\sqrt{\frac{-gR}{sin2x}}\]

Answer 2

i need to find the partial of g

if g=always negative and range is always positive and 0<x<90

Answer 3

since sin is always positive in my angle

Answer 4

the bottom is always positive and the top is always positive

Answer 5

\[\frac{\delta f}{\delta g}=\frac{1}{sin2x}\frac{\delta}{\delta g}(\sqrt{-gR})\]

Answer 6

@Zarkon @myininaya

Answer 7

i'm missing a square root for sin2x when i pulled it out

Answer 8

This is what you are looking for :
\[v_{o_{g}}\]
?

Answer 9

yes however g is gravity = -9.81m/s^2

R= range =always positive

and 0<x<90

Answer 10

should i just pull out sin 2x or do it with to awingspan for all angles

Answer 11

however it's for a projectile motion.= /

Answer 12

well sin(2x)>=0 on the interval [0,pi/2]
So you can say
\[v_{o_{g}}=\frac{1}{\sqrt{\sin(2x)}} (\sqrt{-g R})_g\]

Answer 13

Treat -R like a constant multiple

\[((g \cdot [-R])^\frac{1}{2})_g \text{ hint : Use chain rule and treat -R as a constant multiple }\]

Answer 14

yeah i know for that i'm just wondering that if

0<2x<90

so it's always positive so i can split it