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How do I find the horizontal asymptote of 1/(x+7)+3? Show work please.
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\[\Large \frac{1}{x+7}+3\] \[\Large \frac{1}{x+7}+3*\frac{x+7}{x+7}\] \[\Large \frac{1}{x+7}+\frac{3(x+7)}{x+7}\] \[\Large \frac{1}{x+7}+\frac{3x+21}{x+7}\] \[\Large \frac{1+3x+21}{x+7}\] \[\Large \frac{3x+22}{x+7}\] So \[\Large \frac{1}{x+7}+3\] simplifies to \[\Large \frac{3x+22}{x+7}\] Let me know if you can take it from here
I'm still confused on how to get the horizontal asymptote.
What are the leading coefficients for \[\Large \frac{3x+22}{x+7}\]
3 and 1?
now divide them to get the horizontal asymptote: 3/1 = 3 So the horizontal asymptote is the equation y = 3
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oh ok, thanks so much!
np
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