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Chemistry 14 Online
OpenStudy (anonymous):

Comparing hexane and octane, which is a stronger london dispersion force and why

OpenStudy (aaronq):

octane does because it has a larger surface area

OpenStudy (anonymous):

what about benzil and benzophenone?

OpenStudy (anonymous):

would it be benzil for the same reason?

OpenStudy (aaronq):

if were talking bout london dispersion forces, then yes. but i'm not sure how their dipole would play out in terms of cancelling out. I think benzophenone would be more polar and thus have greater attraction to one another due to these partial positive/negative charges

OpenStudy (anonymous):

i thought both of them were non-polar molecules

OpenStudy (aaronq):

they are, but benzil has Oxygens in somewhat different orientations while benzophenone has only one oxygen and it's dipole is concentrated in one direction. remember that dipoles have directional magnitude

OpenStudy (anonymous):

for the dipole-dipole forces i just said that the two of them dont't have any because they are both non-polar.

OpenStudy (anonymous):

london dispersion forces are present in all molecules right?

OpenStudy (aaronq):

sorry i thought you said they're polar, they ARE polar. unequally distributed sharing of electrons in the carbonyl group

OpenStudy (aaronq):

yep, london dispersion forces are always there

OpenStudy (anonymous):

okay, and how about 2-napthol and naphthalene - i said that 2-nepthol has the greatest dispersion force since the molecules are pratically identical, only 2-nepthol has an extra O

OpenStudy (anonymous):

and you said that benzil and benzophenone are polar? i thought they were non-polar

OpenStudy (aaronq):

you're right about 2 nephtol, but it is because it is an alcohol and thus it is capable of hydrogen bonding (which is a polar characteristic)

OpenStudy (anonymous):

im asking a million questions at once haha im sorry,

OpenStudy (anonymous):

i didnt think there was h bonding in 2-napthol

OpenStudy (anonymous):

hydroxide counts as a hydrogen bond?

OpenStudy (aaronq):

there is, anytime you have an alcohol you have hydrogen bonding when you have H attached directly to O, N or F you are capable of H-bonding

OpenStudy (aaronq):

yes

OpenStudy (aaronq):

haha it's okay, I'm glad i can help someone who's into chem

OpenStudy (anonymous):

so the presence of the OH is what also makes the london dispersion force stronger?

OpenStudy (aaronq):

by the way benzil>benzophenone is terms of polarity

OpenStudy (anonymous):

does this make it more polar?

OpenStudy (anonymous):

and haha i really do enjoy chemistry : )

OpenStudy (aaronq):

well, what you mean presence of OH, you mean in solution?

OpenStudy (aaronq):

haha thats good, it gets really really complex

OpenStudy (anonymous):

there is an OH attached to a C in 2-napthol that isn't in naphthalene

OpenStudy (aaronq):

yep thats a hydroxide, which makes 2-naphtol an alcohol, hence the suffix -ol

OpenStudy (anonymous):

and both are polar, correct?

OpenStudy (aaronq):

yep, both are polar. if you have elements highly electronegative, typically, you;ll have a polar molecule

OpenStudy (anonymous):

how do i tell which one has the dtronger dipole-dipole force?

OpenStudy (aaronq):

thats something you have to calculate by finding their dipole moment. but you can usually eye it out based on the number of the electronegative atoms and their angles

OpenStudy (anonymous):

okay because their surface areas look about the same

OpenStudy (anonymous):

oh wait, that's for dispersion forces.

OpenStudy (anonymous):

not sure how to tell which has the stronger dipole-dipole or dispersion force since they're so similiar

OpenStudy (anonymous):

does the presence of OH make 2-napthol have a stronger dispersion force?

OpenStudy (aaronq):

they're kinda similar but not really.. if you have to compare 2 molecules and one has a dipole and the other has no dipole (non-polar), automatically, the one with the dipole has greater intermolecular forces

OpenStudy (anonymous):

but both have dipole-dipole forces and i need to state which is stronger and why

OpenStudy (aaronq):

say because on has a greater dipole moment.. |dw:1349310614054:dw|

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