Question

Redox Reaction: Express answer as a chemical equation, identify all the phases in answer
(equation below)

Answer 1

\[MnO _{4}^{-}(aq) + Al(s) \rightarrow Mn ^{2+}(aq) + Al ^{3+} (aq)\]

Answer 2

I am confused because when i do out each half reaction, i end up with my electrons on the same side which doesn't allow me to cancel them.

Answer 3

I don't think the electrons are on the same side for this,
\[MnO_4^-+Al \rightarrow Mn^{2+}+Al^{3+}\]
\[5e^{-}+8H^{+}+MnO_4^-\rightarrow Mn^{2+}+4H_2O \\ \\ Al \rightarrow Al^{3+}+3e^{-}\]
Balncing charges
\[5e^{-}+8H^{+}+MnO_4^-\rightarrow Mn^{2+}+4H_2O ~~(\times3) \\ \\ Al \rightarrow Al^{3+}+3e^{-} ~(\times 5)\]
Then finish up by combining equations.
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If electrons are on the same side, you flip one of the equation.
\[Note~ that: \\ \\ \Delta H \text{ sign will flip} \\ \\ E^{o} \text{sign will flip}\]

Answer 4

why is the electron count/charge (or whatever you want to call it) for permangenate 5e?

Answer 5

so i should end up with \[24H ^{+} + 3MnO _{4}^{-}+5Al \rightarrow 3Mn ^{2+} + 12 H _{2}O + 5Al ^{3+}\]