Question

What is the derrivative of y= 1+cos x/1-cos x ?

Answer 1

Quotient ruuuuuuuuuuuule \:D/
Do you remember the quotient rule? c:
\[(\frac{ u }{ v })'=\frac{ u'v-uv' }{ v^2 }\]

Need help with the setup? :O

Answer 2

so i have this:
\[y= \frac{ (1 -\sin x)(1-\cos x) - (1 +\sin x)(1+\cos x }{ (1-\cos x)^{2} }\]

now what do I do?

Answer 3

(1+cosx)' = (0-sinx)
Remember, the derivative of a constant is 0! :D
Fix those spots up c:

Answer 4

\[y= \frac{ (-\sin x)(1- \cos x) - ( \sin x)(1+\cos x) }{ (\cos x)^{2}}\]

Answer 5

Yah looks good c:
You could multiply out the brackets if you want.. I don't think this one will simplify very far though :O I could be wrong :D

Answer 6

how would i do that?

Answer 7

Oh i guess i was mistaken, if you multiply out the other one, you should have a nice cancelation c: