Question

I need help with an algebra question! I am going to attach it below! Thank you! Please help me!! :) Please help, the one whp was helping is not here now, please!!!!!

Answer 1

whats the question

Answer 2

I attached the file that contains the question!

Answer 3

ok im sorry i dont know this but i can get some who knows this ... sorry:)

Answer 4

thank you

Answer 5

no problem

Answer 6

I can't open the file, but from the file name, it looks like a projectile motion situation.

Answer 7

oh you cant? what should i do?

Answer 8

Can you type out the relevant info?
Initial height = ____
velocity = ____
what is to be solved for?

Answer 9

i can tell u the problem

Answer 10

An object is thrown upward from a height of 6 feet at a velocity of 65 feet per second.
t1 = 0, t2 = 3
(a) Use the position equation
s = −16t^2 + v0t + s0
to write a function that represents the situation.
s =

Answer 11

thank you @sk84life

Answer 12

u got it :D

Answer 13

It looks like you put in the value of t to solve for the height.

Answer 14

The initial height of 6 feet is your s_0.

Answer 15

v_0 = 65 ft/s

Answer 16

So the function is s = -16t^2 + 65t + 6, right?

Answer 17

Yep.

Answer 18

I still have few more parts of the question, pls wait! brb

Answer 19

(c) Find the average rate of change of the function from t1 to t2.

Answer 20

Avg. rate of change: f(x1) - f(x2)
-----------
x2 - x1

Answer 21

Yep, good ol' slope formula.
plug in (one at a time), the values of t1 and t2 to get the initial and final heights, and divide by t2-t1.

Answer 22

is it 17? 57 -6
------
3

Answer 23

Yeah, that looks right. Do you know the units of measurement for that number?

Answer 24

sec?

Answer 25

It's seconds for the time and feet for the height, and one of those is being divided by the other.

Answer 26

so?......

Answer 27

The rate of change in this case is the average vertical speed, so it needs to have units appropriate for a speed.

Answer 28

ft per sec?

Answer 29

Exactly. The speed is slowing down as it goes up (gravity is a drag like that..), but the average speed over those first 3 sec. is 17ft/s.

Answer 30

oh...it applies only to those first 3 sec?

Answer 31

@CliffSedge

Answer 32

Yes, the 17ft/s is an average taken over 3 seconds. t1 to t2. The speed started at 65ft/s and after 3s will slow to a stop and start coming back down at 57ft/s.

Answer 33

the next part is: Find the equation of the secant line through t1 and t2.
I got: y = 17x + 6, but my site says that its wrong

Answer 34

its the last part please help me @CliffSedge

Answer 35

am I supposed to put t instead x, is that the mistake?

Answer 36

Maybe.. the information is in terms of t.

Answer 37

i will try that.....but only got 1 submission left....so then why did they say y?

Answer 38

Ah, the function is s(t)

Answer 39

It might be your variable names.

Answer 40

isnt it supposed to be s?

Answer 41

It shouldn't really matter. Variable names are arbitrary, but it's best to stay consistent with whatever the problem calls them.

Answer 42

so u want to me to replace x with y?

Answer 43

The secant line ought to be s=17t+6

Answer 44

there got it! Thank you SO MUCH!!!!! :)