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Mathematics 14 Online
OpenStudy (anonymous):

a man whose height is 1.8m is walking directly away from a lamp fast at contrite of 1.2m/s. if the lamp s 12m above the ground, find the rate of which shadow is lengthening

OpenStudy (anonymous):

this is about time rates on differential calculus

OpenStudy (anonymous):

have you tried drawing a picture yet

OpenStudy (anonymous):

not yet :(

OpenStudy (anonymous):

draw a picture, then figure out the equation where input is distance away from the lamp and out put is length of the shadow

OpenStudy (anonymous):

|dw:1349318841236:dw|

OpenStudy (anonymous):

then find the derivative in respect to t

OpenStudy (anonymous):

dx/dt would be velocity which would be 1.2 and ds/dt would be rate the shadow increases over time

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