a man whose height is 1.8m is walking directly away from a lamp fast at contrite of 1.2m/s. if the lamp s 12m above the ground, find the rate of which shadow is lengthening

Question

anonymous · Answer

this is about time rates on differential calculus

anonymous · Answer

have you tried drawing a picture yet

anonymous · Answer

not yet :(

anonymous · Answer

draw a picture, then figure out the equation where input is distance away from the lamp and out put is length of the shadow

anonymous · Answer

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anonymous · Answer

then find the derivative in respect to t

anonymous · Answer

dx/dt would be velocity which would be 1.2

and ds/dt would be rate the shadow increases over time