For what values of a and b are y = a bx and y = 2 + x tangent at x = 0.
it should be y=a*b^x
please clarify you are asking Y=a*b^x to be tangent on Y=2+x at x=0.. OR both Y=a*b^x & Y=2+x both be a tangent on x=0
y=a*b^x is tangent at y=2+x at x=0
i need to find the values for a and b
i know that the point is (0,4) and the derivative of of y=ab^x is y'=ab^x*ln(b)
so the slope at x=0 is 1
here derivative of y=2+x will give the slope of y=a*b^y
what?
why would you need the derivative of y=2+x
its just a line
see on derivating a function we get the slope of its tangent at a given point.
yeah but y=2+x is the line tangent to ab^x
according to you question "y=a*b^x is tangent at y=2+x at x=0 "this would be the approach.
no dude you dont know
you dont need the derivative of y=2+x we need the derivative of y=ab^x
yeah that i knw but in question u typed something else..anyways i will get back to u in 5 minutes ..need to solve on paper.
i did not!
okay.but plz clarify one more thing the curve is Y=a*b^x or y=(a*b)^x.?
i got it
dont wory about
my answer.a=2;b=e^0.5...is it correct?
yes
thanx.
Join our real-time social learning platform and learn together with your friends!