Question

Question ? @UnkleRhaukus

Answer 1

http://myfuture.edu.pk/Data/fast/physics_1.gif

Answer 2

why me

Answer 3

Come on boss help me out ?

Answer 4

lol total resistance is 1+2+3 = 6 ohm (series connection)
by ohms law . I = V/R
2 amps

Answer 5

are you toying with us ?? @hba

Answer 6

Not at all boss @vikrantg4

Answer 7

\[V=IR\]

\[I=V/R\]


\[V=12[V]\]
\[R=R_1+R_2+R_3\]
\[R_1=1[\Omega];\qquad R_2=2[\Omega];\qquad R_3=3[\Omega]\]

Answer 8

\[I=\frac{12[V]}{1[\Omega]+2[\Omega]+3[\Omega]}=\frac{12}{1+2+3}\frac{[V]}{[\Omega]}=\frac{12}{1+2+3}[A]\]

Answer 9

hey man why are you doing so efforts to write it ? :P

Answer 10

\[%\]

Answer 11

@vikrantg4
Because i am a scientist, not an engineer