Question

3/x+13/x-11

Answer 1

\[\left[\begin{matrix}3 & 13 \\ x & x-11\end{matrix}\right]\]

Answer 2

are they fractions or are they dividends?

Answer 3

there fractions being added.

Answer 4

sorry forgot to write that

Answer 5

i think it is
\[\frac{3}{x}+\frac{13}{x-11}\] but i could be wrong

Answer 6

in any case add fraction the same way you always do
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bc}\]

Answer 7

Thats exactly how you write it

Answer 8

if i am right in the question, you should get
\[\frac{3(x-11)+13x}{x(x-11)}\]which you can clean up with some algebra

Answer 9

\[\frac{3}{x}+\frac{13}{x-11}\]\[\frac{3(x-11)+13x}{x^2-11}\] would that be right @satellite73

Answer 10

if you multiply out in the denominator it will be \(x^2-11x\)

Answer 11

Im really confused can you do it step by step?

Answer 12

btw i made a typo above, it should be
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

Answer 13

@toriebabii did you see what i wrote above about adding fractions? it is the same way with variables as with numbers
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]

Answer 14

in your case \(a=3,b=x,c=13,d=x-11\)

Answer 15

put them directly in to the right hand side of the method for addition
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\] with careful use of parentheses, and you will get the answer

Answer 16

so then like mine said it would be: 3x+13x−11
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd}\]\[\frac{3}{x}\frac{13}{x-11}\]\[\frac{3(x-11)+13x}{x(x-11)}

Answer 17

\[*\frac{3(x-11)+13x}{x(x-11)}*\]

Answer 18

and thats the answer?

Answer 19

no, now you simplify.
\[\frac{3(x-11)+13x}{x(x-11)}\]\[\frac{3x-33+13x}{x^2-11}\]\[\frac{16x-33}{x^2-11}\] do you see anything wlse to do in this equation?

Answer 20

i believe that would be the answer.