Question

log 7 √ 49

Answer 1

first off, \(\sqrt{49}=7\) right?

Answer 2

\[\sqrt{7} 49\]

Answer 3

so you are being asked for
\[\log_7(7)\]
which must be 1, because you are being asked "raise 7 to what power to get 7?" and the answer is 1

Answer 4

now i am lost

Answer 5

what is the base of your log? what is the input?

Answer 6

if you have this as base 10 then you are multiplying 7 by 7=49
log49

but if it is base 7, follow what @satellite73 said

Answer 7

log sqrt 7 bqase 49

Answer 8

Base**

Answer 9

lol what?

Answer 10

\[\log_{49}(\sqrt{7})\]?

Answer 11

base is 49, input is \(\sqrt{7}\) right?

Answer 12

trick is to try to write with exponents, because
\[\log_b(x)=y\iff b^y=x\] so you are trying to solve
\[49^y=\sqrt{7}\]

Answer 13

we see that \(49=7^2\) and \(\sqrt{7}=7^{\frac{1}{2}}\) so what you want is
\[7^{2y}=7^{\frac{1}{2}}\] or
\[2y=\frac{1}{2}\] or
\[y=\frac{1}{4}\]

Answer 14

meaning is simpler english that the number \(\sqrt{7}\) is the fourth root of 49