Question

MORE URGENT

What is the simplified form of the expression?

http://i1255.photobucket.com/albums/hh639/zigzagoon20001/Equation_zpsd593ffb9.jpg

A. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/A_zps270408ca.jpg

B. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/B_zps8ce036fb.jpg

C. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/C_zpsacb1dea7.jpg

D. http://i1255.photobucket.com/albums/hh639/zigzagoon20001/D_zps1ff35b19.jpg

A, B, C, or D? Please explain (:

Answer 1

@zigzagoon2000 Do not, under any circumstances, close and repost a question to bypass our bump limits. Thanks.

Answer 2

Will do

Answer 3

Help anyone?

Answer 4

hi zigzagzoon. let me take a look at your problem first.

Answer 5

hey. alright.

Answer 6

ok got it

Answer 7

now this problem is about using laws of exponents.

Answer 8

alright..

Answer 9

in this case, the x and the y serve as bases of the exponents. you want to consider like bases and add their exponents.

Answer 10

so, for instance, lets say we had 2^3 times 2^5, then that equals 2^8. do you see this?

Answer 11

then it would 16

Answer 12

in this case, 2 served as the base, but the principal is the same.

Answer 13

wait... dang it hold on

Answer 14

512, yes?

Answer 15

wait... i may have confused the issue for u. the 2^8 was an example, not the answer to your particular problem. ok?

Answer 16

ok..

Answer 17

so now you have two numbers in the given product. it is perfectly legal to multiply them and put them out front.

Answer 18

so far so good?

Answer 19

confused at this point tbh

Answer 20

ok, then lets back up. tell me where you need to start. :)

Answer 21

still there zigzag?

Answer 22

i need to start at the very beginning.

Answer 23

perfect. then that is where we start. :)

Answer 24

lets take a different tack.

Answer 25

let us start by reorganizing the product using the commutative property for multiplication. lets get the numbers and x's next to eachother so we can work on them

Answer 26

so, using the commutative property, we can rewrite the given product as
5 times 2 times x^8 timesx^5 times y^10.

Answer 27

is there any question about what i just did? i rearranged terms using the commutative property of multiplication (since this is a string of products, we can do that)

Answer 28

now stay with me... we're gonna getcha through this. :)

Answer 29

okay, i'm still here, hold on a sec lemme see what i'm looking at

Answer 30

:) understood

Answer 31

"5 times 2 times x^8 timesx^5 times y^10" how do i do THIS haha

Answer 32

what do x and y equal?

Answer 33

this is an expression, not an equation. nothing to solve and no substitutions are instructed (like substitute 3 for x and 2 for y). this is about the laws of exponents using variable bases.

Answer 34

i am gonna walk you through this. ok?

Answer 35

first, multiply the 2 and the 5 and put their product out front. In these product problems, first multiply numbers with numbers.

Answer 36

alright, so.. 5 * 2 = 10

Answer 37

then we will tackle the product of x^8 and x^5 because here we will use the law of exponents for like bases.

Answer 38

when you have like bases, whether numbers or variables, you can add their exponents.

Answer 39

so that means x^5 times x^8=?

Answer 40

notice that i am breaking the problem up for instructional purposes, but bear in mind that as we condense terms, the expression remains a product of these condensed terms.

Answer 41

you are awfully quiet zigzagzoon. :) talk to me

Answer 42

alright, so you're saying x = 3, right?

Answer 43

bear with me haha

Answer 44

no, i am saying that x has no given value, and neither does y

Answer 45

what matters here, confusing as it is, is the ability to multiply terms with exponents and like bases

Answer 46

alright so 5 * 8 = 40, not sure where to put the x's

Answer 47

you add the exponents, so that x^5 times x^8=x^13

Answer 48

i'm confused on how to add the exponents

Answer 49

so now you have 10(x^13)(y^10)

Answer 50

ugh... i think i somewhat get it, but don't hold me to that lol

Answer 51

ok. in the given expression, 2^3 times 2^5, 2 is the base and 3 and 5 are the exponents. so to get this product, since the product is of exponents with the same base, we can add their exponents to get 2^8. this is just mathematical shorthand for saying
(2 *2*2*2*2)*(2*2*2*2*2*2*2*2)=count the 2's and you get the exponent.
in this case x^5 has a base of x and an exponent of 5. it is the same as saying
x*x*x*x*x

Answer 52

mkay, well thank you :D

Answer 53

you are still having trouble arent you?

Answer 54

a little bit, but i got that last part you said: "this is just mathematical shorthand for saying
(2 *2*2*2*2)*(2*2*2*2*2*2*2*2)=count the 2's and you get the exponent.
in this case x^5 has a base of x and an exponent of 5. it is the same as saying
x*x*x*x*x" so i kinda understand i guess

Answer 55

god i hate math haha

Answer 56

right so lets take a look at an example that is simpler. bear with me.

Answer 57

let's look at the product of x^2 and x^3.

Answer 58

alright bear with me as well, i just wanna make sure i get this right. um, where do i start off on this one? what is the first thing i do?

Answer 59

start with the product of the numbers 2 and 5

Answer 60

what do i do with those numbers?

Answer 61

put the 10 out in front. numbers go first in variable expressions because it is good form

Answer 62

we are back to your problem.

Answer 63

you are still thinking that the variable have to have a value attached somehow

Answer 64

yes, x^2, x^3. somehow i got 10, how is that? where did the product of the numbers come from?

Answer 65

oh. it is not the product of the exponents. it is the sum

Answer 66

ADD 2 and 3

Answer 67

it is the sum? but where did 5 and 2 come from, when the question was x^2, x^3??

Answer 68

trust me, i feel really stupid right now

Answer 69

i suck at math

Answer 70

oh, it came from your original problem and i stupidly re addressed that for clarification. sorry, i had a duh moment here

Answer 71

lol

Answer 72

alright, so back to x^2, x^3. and it's all good haha, you're helping ME lol

Answer 73

so for the product of x^2 and x^3, the answer is x^5.

Answer 74

notic i added the exponents

Answer 75

yes because 2 + 3 is 5, so it would become x^5

Answer 76

i noticed

Answer 77

(:

Answer 78

yes. as long as the base is the same, in this case, x, you can add the exponents.

Answer 79

the exponents are the numbers right?

Answer 80

yes. they are the numbers. now, do you see how this applies in your original product?

Answer 81

you are getting there. be kind to yourself and you will get it faster :)

Answer 82

thank you, and i kinda but i mean the original was variables to certain powers

Answer 83

right, so add the exponents of the like bases

Answer 84

ugh, i need a cigarette, hold on

Answer 85

lol

Answer 86

so, for the original problem. 1) regroup the string of products. put numbers with numbers and like bases with like bases like this: (2x5)(x^5timesx^8)y^10.

Answer 87

2) carry out the multiplication of the the numbers to get 10.

Answer 88

hold on, please

Answer 89

3) add the exponents of like bases.. in this case, the like bases are x to get x^(5+8)=x^13

Answer 90

i am holding :)

Answer 91

first off, the bases are the variables? you're confusing me lol

Answer 92

in this problem, yes, the x in x^5 and x^8 are the bases. variables can be bases. what is confusing you is that this not a problem about doing math, this is a problem concerning mathematical notation

Answer 93

yeah.. math confuses me lol

Answer 94

that is why the variables are not given values. this is all about notation of bases and exponents.

Answer 95

okay lemme try. gimme a sec

Answer 96

okeedokee. i am all for it. fire away...:)

Answer 97

Okay, original problem: x^8 * 2y^10 * 5x^5

You said to regroup the string of products.

Then you said: "put numbers with numbers and like bases with like bases".

Can you reword that for my stupid a-s-s, if possible to make it more simple for me, cause this is like my first time doing math like this or anything like it, algebra, geometry, graphs, etc. Even fractions. Have not done them ever, dropped out, started doing online schooling and got my answers online from other people like yourself. *sighs* So yeah. Please bear with me, and also um..reword it..please? Sorry if I said "please" or "sorry" too much. *sighs again*

Answer 98

no problem. i can tell you are frustrated.