Question

For the equation given below, evaluate y' at the point (-1,1).

(2 x - y)^4 + 2 y^3 = 83

Answer 1

start with
\[4(2x-y)^3(2+y')+6y^2y'=0\] replace \(x\) by \(-1\) , \(y\) by \(1\) and solve for \(y'\)

Answer 2

oops typo there
\[4(2x-y)^3(2-y')+6y^2y'=0\]

Answer 3

-108(2-y')+6y'=0?