* I'll answer your questions pertaining to English, Psych, and Philosophy if you help me with mine? What is the equation of the line passing through (-6, 1) and perpendicular to the line y = -3x + 1 in slope-intercept form? a.) y = 3x + 4 b.) y= 1/3 x +3 c.) y = -3x - 6 d.) y= -1/3 x - 5
perpendicular to a line with slope \(-3\) means slope will be \(\frac{1}{3}\) the "negative reciprocal" there is only one choice of answer with slope \(\frac{1}{3}\)
i.e. it is B no need for further computation
Wait how did the negative reciprocal come to mind there?
Viewing the problem I didn't even come across that thought
I got b without the negative r
Math is so complicated, how do you know this so well.....?
because i know that if a line with slope \(m_1\) is perpendicular to a line with slope \(m_2\) then \[m_1m_2=-1\] i.e. \[m_1=-\frac{1}{m_2}\] and \[m_2=-\frac{1}{m_1}\]
OHHHHHH it's asking for perpendicular, so the opposite....yes?
Now i understand
you have to know this to do the question. to find the equation of a line you need a slope and a point if you are not given the slope, you have to find it somehow
\[m_1m_2=-1\]Where did this come from @satellite73
@wio I think he is referring to the negative reciprocal
I know the negative reciprocal, but he used that to show the negative reciprocal, not the other way around.
You're right, I saw it as how it should've been
Minor mistake on his part
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