Question

I Need Help With This Problem!?!?!

Answer 1

I don't remember how to do that. Sorry.

Answer 2

\(a^0=1\) might help

Answer 3

Nope, still don't remember how.

Answer 4

It's Ok. Thanks Anyways.

Answer 5

Okay. a^1 is a, by definition.
a^0 is 1 (this can be seen by using the laws of dividing exponents, since any number divided by itself is 1)
a^-n is 1/a^n (This is because raising one power is multiplying a by itself, but subtracting 1 from the exponent of a^0 is 1/a, and so on)
1/a^-n is a^n, by the same logic.