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OpenStudy (anonymous):
I Need Help With This Problem!?!?!
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OpenStudy (anonymous):
OpenStudy (anonymous):
I don't remember how to do that. Sorry.
OpenStudy (anonymous):
\(a^0=1\) might help
OpenStudy (anonymous):
Nope, still don't remember how.
OpenStudy (anonymous):
It's Ok. Thanks Anyways.
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OpenStudy (anonymous):
Okay. a^1 is a, by definition. a^0 is 1 (this can be seen by using the laws of dividing exponents, since any number divided by itself is 1) a^-n is 1/a^n (This is because raising one power is multiplying a by itself, but subtracting 1 from the exponent of a^0 is 1/a, and so on) 1/a^-n is a^n, by the same logic.
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