An electron inside an electric field region between two parallel plates as shown below is rejected upward at a speed of Vo=5.83x10^6 m/s and at an angle of teta=39.0 degrees ; E=1870 N/C (direct upward), d =1.97cm and L=6.20cm. Will the electron strike one of the two plates? If yes, which plate will it strike and what distance from the left edge?

Question

anonymous · Answer

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anonymous · Answer

how many times are you going to post this problem?

egenriether · Answer

do you have an answer yet?

anonymous · Answer

this has been done for you several times.

egenriether · Answer

@Algebraic!  your picture is so funny!

anonymous · Answer

solve:
.0197= 5.83E6*sin(39)*t -1/2*(qE/m)*t^2
for t...

if there's no solution then the electron never reaches the upper plate.
        then solve
        0=5.83E6*sin(39)*t -1/2*(qE/m)*t^2
        for t
        check the range using:
        x= 5.83E6*cos (39)*t
        if x< .062m then the electron hits the lower plate there.


if there is a solution, find the range from:
x= 5.83E6*cos (39)*t
that's where the electron strikes the upper plate.

anonymous · Answer

sorry guys cause still I can't find the solution yet but i have the answer 4.07 cm, I couldn't figure out the solution