Question

How would you balance the following chemical equation:
C2H2+O2----> CO2+H2O

Answer 1

2C2H2+5O2---->4CO2+2H2O

Answer 2

If you look at the equation on the elft side, the 02 on the left side is by iteslf, which would make it easiest to balance. It is also an even number.
Now, if you look at the right side, the CO2 and H2O have 3 Oxygens. Since 3 is an odd number, you can start by multiplying H2O by 2. Now you have 4x Oxygen on the right side. By a new problem occured, you now have 4x Hydrogen on the right side in comparison to the 2 on the left.
C2H2 + O2 --> CO2 + 2H2O
How do you balance that? You multiply C2H2 by 2. Now the hydrogen are balanced but you have 4x Carbon on the left side and 1 on the right side.
2C2H2 + O2 -> CO2 + 2H2O
Multiply CO2 by 4 and you are now balanced with Carbon and Hydrogen. All that's left is the Oxygen.
2C2H2 + O2 -> 4CO2 + 2H2O
Since there are 2 Oxygen on the left side and 10 on the right side, you multiply O2 by 5 and you get your solution.
2C2H2 + 5O2 -> 4CO2 + 2H2O

Answer 3

Beautiful, thank you so much!

Answer 4

What would the phases be?

Answer 5

What phase is this? @Astrophysics @inkyvoyd @just_one_last_goodbye @Love_Ranaa @Mehek14 @ParthKohli @ShadowLegendX @sweetburger