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OpenStudy (anonymous):
\[h(m-2)=\frac{ 5 }{ (m-2)+2 }\]
OpenStudy (anonymous):
I'm not sure what the question is asking but:\[h(m-2)=\frac{ 5 }{ (m-2)+2 }\]\[h(\ \ )=\frac{ 5 }{ (\ \ )+2 }\]\[h(x)=\frac{ 5 }{ (x)+2 } = \frac{ 5 }{ x+2 }\]Is \(h\) some function or a variable you're solving for...?
OpenStudy (anonymous):
yeas it is :)
OpenStudy (anonymous):
we need it to be simplified also
OpenStudy (anonymous):
You said 'yeah' to an or question so.... I'm not sure which it yet.
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OpenStudy (anonymous):
to solve h is why i said ya
OpenStudy (anonymous):
Well is \(h\) a function or not?
OpenStudy (anonymous):
yea
OpenStudy (anonymous):
So it is a function.
OpenStudy (anonymous):
yea
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OpenStudy (anonymous):
i need to know what 'h' equals
OpenStudy (anonymous):
You see what I did there?\[h(x) = \frac{5}{x+2}\]
OpenStudy (anonymous):
is it continued from above?
OpenStudy (anonymous):
\[h(m-2) = \frac{5}{(m-2)+2}=\frac{5}{m} \]
OpenStudy (anonymous):
To be honest, I'm still not sure what the question is.
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