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Mathematics 15 Online
OpenStudy (anonymous):

help Show work plz :)

OpenStudy (anonymous):

\[h(m-2)=\frac{ 5 }{ (m-2)+2 }\]

OpenStudy (anonymous):

I'm not sure what the question is asking but:\[h(m-2)=\frac{ 5 }{ (m-2)+2 }\]\[h(\ \ )=\frac{ 5 }{ (\ \ )+2 }\]\[h(x)=\frac{ 5 }{ (x)+2 } = \frac{ 5 }{ x+2 }\]Is \(h\) some function or a variable you're solving for...?

OpenStudy (anonymous):

yeas it is :)

OpenStudy (anonymous):

we need it to be simplified also

OpenStudy (anonymous):

You said 'yeah' to an or question so.... I'm not sure which it yet.

OpenStudy (anonymous):

to solve h is why i said ya

OpenStudy (anonymous):

Well is \(h\) a function or not?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

So it is a function.

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

i need to know what 'h' equals

OpenStudy (anonymous):

You see what I did there?\[h(x) = \frac{5}{x+2}\]

OpenStudy (anonymous):

is it continued from above?

OpenStudy (anonymous):

\[h(m-2) = \frac{5}{(m-2)+2}=\frac{5}{m} \]

OpenStudy (anonymous):

To be honest, I'm still not sure what the question is.

OpenStudy (anonymous):

i need to find what h is

OpenStudy (omnomnom):

he means H as a variable

OpenStudy (anonymous):

@NeedMathHelpBad is \(h\) a variable?

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