Question

help

Answer 1

\[h(m-2)=\frac{ 5 }{ x+2}\]
find h

Answer 2

ok

Answer 3

get h alone first

Answer 4

h= 5/(x+2) - m-2

Answer 5

there is h

Answer 6

\[\frac{ 5 }{ (x+2)(m-2) }\]

Answer 7

\[f(x+1)=a^2\]
find f

Answer 8

\[\frac{ a ^{2} }{ (x+1) }\]

Answer 9

show work?

Answer 10

see how Im getting these?

Answer 11

plz show work :)

Answer 12

just have to divide both sides by x+1

Answer 13

you want F alone so you have to do the opposite of whats there.

Answer 14

p(-3)=3x-5
solve for p

Answer 15

it the same as if you had 2f=a^2 you would have to divide by 2

Answer 16

So what would you do for this one?

Answer 17

p=3x-5(-3)
p=-9-neg 15

Answer 18

your plugging -3 in you need to solve for p

Answer 19

\[P=\frac{ 3x-5 }{ -3 }\]

Answer 20

what class is this?

Answer 21

alg 2

Answer 22

q(3)=x^2-x

Answer 23

does he want you to plug these into the function or write what Ive been writing

Answer 24

Continue what we have and like the other ppl have

Answer 25

these are all the same your just dividing by the 3 to get the q alone

Answer 26

unless he means q(x) where you plug them in

Answer 27

yea
q(x)=x^2-x
q(3)

Answer 28

\[q=\frac{ x ^{2}-x }{ 3 }\]

Answer 29

oh then ignore my equations and just plug in

Answer 30

so that one would be 6

Answer 31

3^2-3

Answer 32

Erase the other ones if your solving by plugging them in

Answer 33

give me them again and Ill redo

Answer 34

1. f(x+1)
f(x)=a^2

2. p(x)=3x-5
p(-3)

3. q(x)=x^2-x
q(3)

Answer 35

1. I think is just a^2+1
2. 3(-3)-5=-13
3)3^3-3=6

Answer 36

ok i need work shown for it to count

Answer 37

I did show work on last 2 1) F(x+1)= (a^2)+1

Answer 38

BTW sorry it took sol long for me to answer i was eating dinner

Answer 39

I need to get going as well

Answer 40

q(1/3)
q(x)=x^2-x

Answer 41

so what are you asking here?

Answer 42

to plug in q(1/3) into q(x)=x^2-x

Answer 43

so where ever you see an x you need to put in 1/3 so do that and show ne what you got

Answer 44

and to solve for q like we were eairler
q(1/3)=1/3^2-1/3

Answer 45

no i think you sould do q= 1/9 -1/3
then you should simplify that so make 1/3 into 3/9
then you have 1/9-3/9 which =-2/9
then you have q= -2/9

Answer 46

i think i am confused at what your homework is can you please type a problem as it is shown on your homework because i might have been doing it wrong. it could be 2 types of problems

Answer 47

10. P(x)=3x-5
p(2/3)
Plug in and solve p

Answer 48

ok so i think is asking p(x)=3x-5 and that if a function so i think it is saying that they want you to plug it in and find out what P(2/3)= which is when you plug 2/3 into the x when its on the right side so it would be p of 2/3= 3*(2/3 )-5 so then you have 2/5 which equals -3 so p of (2/3) = -3 .. so the answer to thet would be -3 id there an example problem on your homework

Answer 49

can u write it out step by step:
Ex;
q(x)=x^2-x
q(1/3)=x^2-x
q=(1/9-3/9=-2/9
q=-2/9

Answer 50

yeah so what do you want me to do ?

Answer 51

this prob u did up ther:
p(2/3)
p(x)=3x-3

Answer 52

P(2/3)=(2/3)-3

Answer 53

p(2/3)
p(x)=3x-3
p(x)=3)(2/3)-3
p(x)=2-3
(x)=-1

Answer 54

p(x)=-1

Answer 55

p(a)
p(x)=3x-3

Answer 56

ok you need to start doing these by ur self or learning
plug in a where x is
on the right side

Answer 57

p(x)=3(a)-3

Answer 58

p(x)=3a-3

Answer 59

now waht

Answer 60

fo p(a)=3a-3 thats the final answer

Answer 61

yay

Answer 62

q(x-2)
Q(x)=x^2-x

Answer 63

q(x^2-2)=x-2-x-2?

Answer 64

now what

Answer 65

on t he left side you dont plug in x-2 only on the right

Answer 66

q(x)=x-2-x-2

Answer 67

q(x-2)
Q(x)=(x-2)^2-(x-2)
then you have to do (x-2)(x-2)that is x^2 -4x+4 -x-2
then you would have x^2 -5x +2 and that is you final answer

Answer 68

r(x-3)
r(x)=x^2+3

Answer 69

r(x)=(x-3)^2+3

Answer 70

correct?

Answer 71

yes !!!

Answer 72

but simply it

Answer 73

x^2 -6x +6 +3
x^2-6x+9

Answer 74

yay
r(b)
r(x)=x^2+3

Answer 75

r(x)=b^2+3

Answer 76

r(b)= that but yes im pretty sure but you might want to get a nother oppinion

Answer 77

i mean r(b(x))= that

Answer 78

ok
q(-4)
q(x)=x^2-x

Answer 79

q(x)=-4-4

Answer 80

q(x)=-4^2-4 Correction*

Answer 81

yeah so do that math out and see what you get

Answer 82

q(x)=16x-4
q(x)=12x

Answer 83

yeah but without the x

Answer 84

im getting better

Answer 85

f(x)
f(x)=a^2

Answer 86

how do i do this one

Answer 87

i dont know

Answer 88

maybe f(x)=x^2

Answer 89

ill ask my teach

Answer 90

f(x+b)
f(x)=a^2

Answer 91

ok well i am getting off of this website for now peace

Answer 92

k :P