Question

how would i make an equation of a line that has a y intercept of 2 and an x intercept of 3? I need a formula I know this for a fact.

Answer 1

Well you know 2 points: (0,2) and (3,0)
find the slope and then pick a point to use in point slope form:

y-y1=m(x-x1)

Answer 2

okay so y-2=m(m-3)

Answer 3

M is the slope, and you use one point in the formula. We'll use (0, 2) so x1=0 and y1=2

but we still need to find the slope so do that first

Answer 4

I have no idea how to do that I havent taken algebra 2 in about 3 years so mind refreshing my memory

Answer 5

i get -2/3

Answer 6

Thats right. So when we plug everything in we get:
y-2=-2/3(x-0)

distribute the -2/3

Answer 7

You should get:
y-2=-2/3x

add the 2 to both sides:

y=-2/3x+2

and that is your answer

Answer 8

yeah see here in lies the problem I only have these to choose from
1. -2X+3Y=4
2.-2X+3Y=6
3.2X+3Y=4
4.2X+3Y=6
5.3X+2Y=6

Answer 9

Oh then it wants it in standard form. Move all the variables to one side

Answer 10

How does that work?

Answer 11

i need to get rid of that fraction first.

Answer 12

Alright, sorry i havent converted to standard form in a while so i had to look it up.

What you wanna do is multiply the whole equation by the lcd to get rid of the fraction. Which would be 3.

Answer 13

so you get 3y=-2x+6

get the x on the same side as y

2x+3y=6

Answer 14

okay

Answer 15

thanks now I get it

Answer 16

You're welcome