Question

Can someone help me on my data from my egg drop project. I have to find TIME OF FALL, MASS OF EGG, MASS OF EGG AND CONTAINER, FORCE TO BREAK EGG. The time of fall from my egg is 1.69 and I drop me egg from a 3 stories building. My egg was 60 grams. Here is a similar container I use http://i.imgur.com/YZtTO.jpg?1

Answer 1

To find the force to break the egg, you have to find the gravitational force, um, could you please remind me what that is? we'll do an equation. which should give you the force of the land in newtons.

Answer 2

By the way, did you actually do this experiment, did the egg break?

Answer 3

oh he's offline XD hey egg, do you know what that is?

Answer 4

brb your answering to, ok, Here I come google!

Answer 5

how long is 3 stories X_X

Answer 6

K.E. = J.0.5732608 heres your answer bro, I will need 20 million dollars in federal funding to find the rest...

Answer 7

You should know the mass of the container (can't help you there). the time of fall can be calculated (neglecting air resistance) by recalling that the distance something falls is D=0.5a*t^2 where D is distance (meters to the the 3rd story) and a=9.8m/s^2. Solve this equation for time. The force is trickier. F=ma, so you would have to know how long it took your egg to come to rest from the initial velocity. This is the acceleration. If it went from 10m/s to 0m/s in 0.5s then the acceleration is 20m/s^2. then F=(mass of egg)*20. (I guarantee your egg was faster) Note this means you'd need to know how long it took your egg to stop moving in the container, since it did not stop instantly (i.e. the box you made provided some cushion, so the egg stopped slowly) How slowly is the question you must answer to calculate the force. This is not that easy of a question!

Answer 8

@HyperChemist my egg did not break

Answer 9

huum, well... oh, and btw I was jking there, I was however able to find the force of the fall of your egg.

Answer 10

Theres no possible way, well, in my mind, to find the force required to break your egg because that would men extra testing in your part, and because the egg was in a container, several things could go wrong, hence not giving a force "required."

Answer 11

@egenriether can you help me what formula should I use

Answer 12

your fall time is t=sqrt(D/4.9) where D is the distance it fell. Again the force is too hard to calculate with the given info, I can't believe they're asking that. The momentum would be easy but the force would require detailed measurements of the impact. I would write what I said earlier, if nothing else your teacher might be impressed that you know how difficult that kind of analysis is.

Answer 13

Also you could find the energy the egg had on impact which is (1/2)(0.06kg)v^2 where v is the terminal velocity of the egg. I know you have everything but the force but I can't calculate that. If you want to try, use F=ma. m=0.06kg for a 60 gram egg. so you now need a, the acceleration. That is the time it took to go from terminal velocity to 0 (again, thats the part you'd need to measure. The equation is (0-V)/t. In other words the final velocity (0 m/s) minus the initial velocity (what speed it was falling when it hit the ground) divided by the time it took to fully stop ( something less than a second). This is the acceleration (in your case deceleration since it will be negative). Sorry I couldn't be more help but I would write all of this in my report since any answer you try to calculate will be based on guess work.