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Chemistry 8 Online
OpenStudy (ookawaiioo):

Someone super smart plzzzz help Can bond order be a negative value?

OpenStudy (aaronq):

MO theory? if the bond order of a molecule is negative it means that the molecule is unstable and does not exist like He2

OpenStudy (ookawaiioo):

Oh thanks..... can i ask you another question?

OpenStudy (aaronq):

yeah, sure

OpenStudy (ookawaiioo):

For the H2+ molecule, absorption of light can cause an electron to be promoted from the σg to the σu* orbital. The equilibrium bond length for the resulting excited molecule will be:

OpenStudy (ookawaiioo):

a. shorter than for H2+ in the ground state. b. longer than for H2+ in the ground state. c. equal to that for H2+ in the ground state. d. None of the above. The molecule is not stable and the will fall apart.

OpenStudy (aaronq):

I'm pretty sure it's d, since the system only has 1 electron, and it is in the anti bonding orbital. I'm studying this stuff myself right now, i have midterm on it tmrw

OpenStudy (ookawaiioo):

Nice.....hmmm..... goodluck......My prof just started on MO theory like a few days ago.

OpenStudy (aaronq):

thanks dude

OpenStudy (ookawaiioo):

What is the bond order of the excited H2+?

OpenStudy (aaronq):

to my knowledge it would be (0-1)/2= -1/2

OpenStudy (ookawaiioo):

A unstable molecule.....hmmmm...... have you had these types of negative bonding order questions before?

OpenStudy (aaronq):

yeah, predicting whether a molecule will exist in real life or not, and proving it. it's more useful than VB a molecule will exist if it's bond order is >0

OpenStudy (aaronq):

MO also shows the paramagnetic property of O2

OpenStudy (ookawaiioo):

Paramagnetic = unshared electrons ?

OpenStudy (aaronq):

unpaired

OpenStudy (ookawaiioo):

ohhhhh thanks..... like He2+?

OpenStudy (aaronq):

yep

OpenStudy (ookawaiioo):

One more question: Bond stretching (asymmetrical, symmetrical, etc) will give higher frequencies if the bond strength is strong?

OpenStudy (aaronq):

the energy or frequency that characterizes the stretching vibration of a given bond is proportional to the bond dissociation energy. straight from my notes; triple>double>single in terms of frequency. similar bond order equates to the strength

OpenStudy (aaronq):

similarly* not similar

OpenStudy (ookawaiioo):

GOTCHA!!!! You da man.....i hope you ace this exam!

OpenStudy (aaronq):

thanks dude! have a good one

OpenStudy (ookawaiioo):

Thanks :D I really do appreciate your help! have a good night!

OpenStudy (aaronq):

no problem man, i like explaining stuff b/c it reinforces my knowledge and i'm able to word things better during examinations. night dude!

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