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Help me write out the proof of "If f(x) is differentiable at a, then f(x) is continuous at a."
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compute \[\lim_{x\to a}[f(x)-f(a)]\]
your move :)
It would be \[\lim_{x \rightarrow a} f(x)-f(a) \div x-a\]
plugging in a will give you 0/0
\[\lim_{x\to a}[f(x)-f(a)]=\lim_{x\to a}\frac{f(x)-f(a)}{x-a}(x-a)=\lim_{x\to a}\frac{f(x)-f(a)}{x-a}\lim_{x\to a}(x-a)=\cdots\]
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I thought you can't directly multiply (x-a) to it since it will change the limit value.
I multiplied and divided by it...so i didn't change the value
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