Question

Sorry, probably a trivial question for most of you out there:
Break down the steps of integrating (definite integral) sin(bx).
How do we arrive at -cos(bx)/b

Answer 1

Let u = bx -> u' = b
∫ sin u dx = ( - 1/u' )cosu + C

Answer 2

Thanks, that makes sense. Why are we dividing by u' again though?

Answer 3

By Integral rule: divided u' ( in opposite with derivative rule : multiply with u'

Answer 4

Thanks :)