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derivative of square root of (lnx)
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so, 1/2x?
forget my above post...it's confusing. so,\[\frac{d}{dx}(\sqrt{\ln x})=\frac{d}{du}\sqrt{u}*\frac{du}{dx}\ln x\]
Here I let u=lnx
we get:\[\frac{1}{2\sqrt{u}}*\frac{1}{x}\]now just put u=lnx back in to express everything in terms of x:\[=\frac{1}{2x \sqrt{\ln x}}\]
make sense?
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Cool thanks, hey, can I ask you another question too? http://openstudy.com/study#/updates/506e28d4e4b088f3c14db4c7
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