Question

How do you find the derivative of 1/(x+7)^-2

Answer 1

Do chain rule.
\[f(x) = \frac{1}{(x+7)^{2}}\] I assume that's the equation you are writing and not \[f(x) = \frac{1}{(x+7)^{-2}}=(x+7)^{2}\]
Here's chain rule if you forgot.
\[f(x) = a*g(x)^{n}\]
\[f'(x) = (n-1)*a*g(x)^{n-1}*g'(x)\]

Answer 2

Ok so would the answer be 2x+14

Answer 3

if your \[f(x) = (x+7)^{2}\] then yes

Answer 4

Thank you!