Question

@simpleish please answer 6, 7, 10

Answer 1

6. Solve for the Angle of the incline first by using:
Tanθ = v^2/rg.
Make sure you convery km/h to m/s for v^2. r = radius. and g = 9.8

Then, use F = mv^2/r
After a ton of substitution and simplifying, you should get:
sqrt(rg(Tanθ -Ustatic)/ (1 + (Ustatic*Tanθ)))

Answer 2

7. Same equation for number six, but instead, signs are flipped. Soo
sqrt(rg(Tanθ + Ustatic)/ (1 - (Ustatic*Tanθ)))

Answer 3

10. Fnet = mv^2/r

Answer 4

and you get (6) Tan(theta) = v^2 / rg from
Nsin(theta) = mv^2/r and using Ncos(theta) = mg to substitute for the N in the first one

Answer 5

pst simpleish, nina's here!