I'm studying a back test for my Mathematical Analysis course, but I'm not sure how to answer one of the questions. Give an example of a sequence {yn} such that lim (n->Infinity) |yn-y(n+1)|=0 but is not a Cauchy Sequence.
i don't have a ready answer, but i have an idea
oh good Q
the difference between this and a cauchy sequence is that this says adjacent elements of the sequence converge to zero, not arbitrary ones
got it
try \(a_n\) as the nth partial sum of the harmonic series
i think that is right, and it generalizes to \[\lim|a_{n+r}-a_n|=0\]
for fixed \(r\) of course.
@Aylin is the answer clear?
I was just about to come back and ask if y{1}=1 and y{n+1}=y{n}+1/n would work.
I think so.
point is the harmonic series diverges, so you can never find an \(N\) such that if \(m,n>N\) you would have \[\sum_1^n\frac{1}{k}-\sum_1^m\frac{1}{k}<\epsilon\] in fact this difference can be made larger than and larger. but \[\sum_1^n\frac{1}{k}-\sum_1^{n+1}\frac{1}{k}=\frac{1}{n+1}\]
Thank you.
yw
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