Question

derivative of (e^x-e^-x)/(e^x+e^-x)

Answer 1

Have you tried using the quotient rule?

Also do you know what:\[\frac{d}{dx}e^x\]is?

Answer 2

it's e^x, right?

Answer 3

yes, what about\[\frac{d}{dx}e^{-x}\]?

Answer 4

no... I think it's -e^-x?

Answer 5

You are correct, you just use the chain rule.

So, the quotient rule is:\[\frac{d}{dx}\frac{f(x)}{g(x)}=\frac{f'(s)g(x)-g'(x)f(x)}{g(x)^2}\]

Do you know how to proceed?

Answer 6

Um, I think so...

Answer 7

d/dx coth(x)

Answer 8

Sorry : d/dx(tanh(x))

Answer 9

I got up to:



is there a way to simplify that?