The rate at which a battery charges is slower the closer the battery is to its maximum charge C0. The time (in hours) required to charge a fully discharged battery to a charge C is given by an equation i'll post as a comment on this in just a sec... where k is a positive constant that depends on the battery. For a certain battery, k = 0.35. If this battery is fully discharged, how long will it take to charge to 70% of its maximum charge C0? (Round your answer to three decimal places.)
\[t= -k \ln (1-\frac{ C }{ C _{o} })\]
What did you get?
I was wondering if the equation once the numbers are plugged in would be \[t=-.35\ln(1-\frac{ 100 }{70})\]?
it's 70/100, not 100/70
\[C /C _{0}=.7\] ln(1-.7)=-1.20397 t=-k*-1.20397 =-.35*-1.20397 =.42139 ~=.421 seconds
t=.421?
Approximately, yes. Do you understand why?
yeah i figured it out!
:)
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