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OpenStudy (anonymous):
\[\lim_{x \rightarrow \infty}\frac{ 5x }{ x+3 }\]
OpenStudy (anonymous):
howsit hatnn
hartnn (hartnn):
divide numerator and denominator by x
OpenStudy (anonymous):
hmmm thats what was confusing me. I just need a course on infinite limits in general my study guide didnt go through it at all.
OpenStudy (anonymous):
\[\frac{ 5 }{ 1+\frac{ 3 }{ x } }\]
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hartnn (hartnn):
here, generally we try to bring the terms in the from of 1/x or 1/x^2 or 1/x^n
so that we can put them as 0
because, when x-> \(\infty\), 1/x^n ->0
yes, so now put 1/x = 0 there.
OpenStudy (anonymous):
so i just have 5
hartnn (hartnn):
yup
OpenStudy (anonymous):
and its like this with every type of lim to infinity?
hartnn (hartnn):
almost every...there maybe some special case where you need to do something else.
in all types of limits with terms x^n
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OpenStudy (anonymous):
could you provide an example of this special case?
hartnn (hartnn):
like trignometric limits,
i can think of this easy one:
lim x->\(\infty\) x sin(1/x)
here u put 1/x=y
OpenStudy (anonymous):
as y? now there are two variables??
hartnn (hartnn):
no, when x-> infinity , y-> 0
so the limit gets converted to
lim y->0 sin y/y
which is 1