A board is comprised of 50 red squares and 50 white squares. You are then given three balls. The balls are then thrown into the board. You then bet on the color majority of the balls will fall into. If you are right, then you win your bet. If not, then you lose your bet. However, on the board are two stars. If you bet on the stars, and any one of your balls fall into the stars, then you win five times your bet. If you lose, you lose five times your bet. Should you play this game?
how big are the stars?
one square
each star
if a ball crosses a star does it automatically fall in /
it has to stop on the square
ok
imagine it as a casino game. each square of the board have walls
stars are neither red or white are they
the point is there are stars on the board..and they are on one of the squares of the board. they are still considered as red/white squares
oh so there is a red star and a white star , ok
you can think of it like that
this is more of a riddle than a math problem. who throws the balls? are we looking at percentages? Chance/probability?
it's definitely a problem
\[\langle \text{expectation value}\rangle\]
no need to think about who throws the balls...and yes @UnkleRhaukus
\[\langle \text{expectation value}\rangle\sim0.45\]
why so?
just a guess
...
i think betting on red or white would have even wins/losses
yes that's what i think too
so would you play it?
well in an even chance game i would expect to get my money back on average but i could still looses all my money , so i wouldn't bet one red/white
what about the stars?
the probability of the first ball landing on a star is 2/100 a
so.. no play?
i havent worked out the probability of any of the three balls landing on a star is yet, but i recon it is less than on in five so i would not bet on this game
makes sense
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