from where do you get the volume of solute..density of NaOH is not given..Okay go on with the volume of solution itself..I think volume of solute is quite negligible
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OpenStudy (anonymous):
We need Density to solve this
OpenStudy (anonymous):
@Vincent-Lyon.Fr
OpenStudy (anonymous):
No..in such problems, usually the solvent is water. So, density is 1
OpenStudy (anonymous):
a solution of NaOH
given:
solute: 19.2 g.
solution is 160cm3
missing: the molality of solution
OpenStudy (anonymous):
change the units of volume to litre and substitute in the formula i had given above
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OpenStudy (anonymous):
Gram Molecular Weight of NaOH = 40
OpenStudy (anonymous):
D = M/V
1 st find density
OpenStudy (anonymous):
What density is required here? @Yahoo!
OpenStudy (anonymous):
D = 19.2/0.16 = 120
OpenStudy (anonymous):
opk.. i'll try to solve :D
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OpenStudy (anonymous):
Take the solvent to be water and volume of solute to be negligible
OpenStudy (anonymous):
Do..u have the answer key @BieberJustin
OpenStudy (anonymous):
For what did you find the density? the mass you substituted was of NaOH and the volume is of solution, which I say is aqueous solution of NaOH
OpenStudy (anonymous):
@BieberJustin Do as I said. If the answer you get does not match with the right answer, I'll quit form Open Study
OpenStudy (anonymous):
*from
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OpenStudy (anonymous):
wait.. just wait.. its not easy for me bro so chill.. :D
OpenStudy (anonymous):
@AbhimanyuPudi
OpenStudy (anonymous):
yep...
OpenStudy (anonymous):
is 3 ur answer @AbhimanyuPudi
OpenStudy (anonymous):
Yes
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OpenStudy (anonymous):
i searched.. the converter said that 160cm3 is 0.16 l ... is this right??
OpenStudy (anonymous):
Yes
OpenStudy (shubhamsrg):
you sure its molality ? should be molarity !! ?? !!
OpenStudy (anonymous):
if it is Molarity then the answer is 3M
OpenStudy (anonymous):
YAH.. SORY ONLY HUMAN.. I HAVE MISTAKE TOO BUT THANKS FOR SAYING THAT :D
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OpenStudy (anonymous):
\[m=\frac{ M }{ d-MM1 }\]
OpenStudy (anonymous):
Molarity and molality turns out to be equal for water if volume of solute is negligible
OpenStudy (anonymous):
So it's molarity?
OpenStudy (anonymous):
so....the question is molarity...)
OpenStudy (anonymous):
yup!
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OpenStudy (anonymous):
oh.......then M = no of moles of solute / 1 L of solution
OpenStudy (anonymous):
so u will get 3M
OpenStudy (anonymous):
its either no of moles of solute in 1L of solution or no of moles of solute / volume of solution...
OpenStudy (anonymous):
my answer is 3
molarity=3
is this right?
OpenStudy (anonymous):
Yes its right
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