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Chemistry 22 Online
OpenStudy (anonymous):

finding for molality..

OpenStudy (anonymous):

molality = number of moles of solute / weight of the solvent

OpenStudy (anonymous):

a solution of NaOH contains 19.2 g. of solute in \[160cm ^{3}\] of solution. what is the molality of the solution.

OpenStudy (anonymous):

I gave you the formula...calculate it...Take care of the units..the answer may be in molal

OpenStudy (anonymous):

how does \[cm ^{3}\] convert to liter?

OpenStudy (anonymous):

Sorry I was on an other ques... \[1cm ^{3}=10^{-6}m ^{3} and 1m ^{3}=10^{3}l\]

OpenStudy (anonymous):

got it boss?

OpenStudy (anonymous):

1CM^3 = 10^-3 L

OpenStudy (anonymous):

what does cm means?

OpenStudy (anonymous):

Can u techeck ur question..i feel some thing is missing

OpenStudy (anonymous):

cm is centi-meter

OpenStudy (anonymous):

a solution of NaOH contains 19.2 g. of solute in 160cm3 of solution. what is the molality of the solution.

OpenStudy (anonymous):

i think the volume of the solution is wrong and its solvent

OpenStudy (anonymous):

solute + solvent = solution solvent = solution - solute

OpenStudy (anonymous):

U have answer key with u

OpenStudy (anonymous):

from where do you get the volume of solute..density of NaOH is not given..Okay go on with the volume of solution itself..I think volume of solute is quite negligible

OpenStudy (anonymous):

We need Density to solve this

OpenStudy (anonymous):

@Vincent-Lyon.Fr

OpenStudy (anonymous):

No..in such problems, usually the solvent is water. So, density is 1

OpenStudy (anonymous):

a solution of NaOH given: solute: 19.2 g. solution is 160cm3 missing: the molality of solution

OpenStudy (anonymous):

change the units of volume to litre and substitute in the formula i had given above

OpenStudy (anonymous):

Gram Molecular Weight of NaOH = 40

OpenStudy (anonymous):

D = M/V 1 st find density

OpenStudy (anonymous):

What density is required here? @Yahoo!

OpenStudy (anonymous):

D = 19.2/0.16 = 120

OpenStudy (anonymous):

opk.. i'll try to solve :D

OpenStudy (anonymous):

Take the solvent to be water and volume of solute to be negligible

OpenStudy (anonymous):

Do..u have the answer key @BieberJustin

OpenStudy (anonymous):

For what did you find the density? the mass you substituted was of NaOH and the volume is of solution, which I say is aqueous solution of NaOH

OpenStudy (anonymous):

@BieberJustin Do as I said. If the answer you get does not match with the right answer, I'll quit form Open Study

OpenStudy (anonymous):

*from

OpenStudy (anonymous):

wait.. just wait.. its not easy for me bro so chill.. :D

OpenStudy (anonymous):

@AbhimanyuPudi

OpenStudy (anonymous):

yep...

OpenStudy (anonymous):

is 3 ur answer @AbhimanyuPudi

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

i searched.. the converter said that 160cm3 is 0.16 l ... is this right??

OpenStudy (anonymous):

Yes

OpenStudy (shubhamsrg):

you sure its molality ? should be molarity !! ?? !!

OpenStudy (anonymous):

if it is Molarity then the answer is 3M

OpenStudy (anonymous):

YAH.. SORY ONLY HUMAN.. I HAVE MISTAKE TOO BUT THANKS FOR SAYING THAT :D

OpenStudy (anonymous):

\[m=\frac{ M }{ d-MM1 }\]

OpenStudy (anonymous):

Molarity and molality turns out to be equal for water if volume of solute is negligible

OpenStudy (anonymous):

So it's molarity?

OpenStudy (anonymous):

so....the question is molarity...)

OpenStudy (anonymous):

yup!

OpenStudy (anonymous):

oh.......then M = no of moles of solute / 1 L of solution

OpenStudy (anonymous):

so u will get 3M

OpenStudy (anonymous):

its either no of moles of solute in 1L of solution or no of moles of solute / volume of solution...

OpenStudy (anonymous):

my answer is 3 molarity=3 is this right?

OpenStudy (anonymous):

Yes its right

OpenStudy (anonymous):

Yup 3M

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