A contractor wishes to build 9 houses, each different in design. In how many ways can he place the houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side?
Its combination i think...@lgbasallote
Nope it is purmutation since it is about arrengement.
he is choosing a slot
Do u have the answer @lgbasallote
9!
The fact you can have facing sides doesn't really make a difference...
i don't @Yahoo!
I think it is about cyclic purmutation Thus the answer will be (n-1)! =8!
it's cyclic?
Cyclic means arranging in circular order.
Why would it be cyclic?
|dw:1349441737492:dw|
Which is the same as |dw:1349441806156:dw| Isn't it?
Which makes it a trivial question really...
I don't agree why u put the lines together?
Why not?
U must have good reason to put them together.
For the first house you have 9 choices, for the second one 8, for the third one 7 etc. Comes down to 9*8*7*6*5*4*3*2*1 = 9!
Here is my way, we can consider the road as the center of the circular arrangement so as to apply cyclic permutation.
|dw:1349442294573:dw|
Which still gives me 9*8*7*6*5*4*3*2*1 choices
It will not. For cyclic permutation the formula is (n-1)!
Slap me around with formulas all you want, i fail to see how 1. The question asks for cyclic permutations 2. (n-1) applies to my drawing...
Besides, i outrank you 65 > 62 ;)
9C6 ?
= 84 ?
is "place" a combination or permutation?
Since the houses have no relations, it's permutation
i guess the order in which houses are kept dont matter,,i.e. if 3,7,8 are on one side,,then 3,7,8 ; 3,8,7 ; 8,7,3 etc are the same,,so i say combination..
ohh wait,,is question like this : 9 houses are there,,6 on 1 side,,3 on other,,and how many different ways can be there to give them 9 different designs ?
do you have an answer ?
i do not
hmm,,maybe i dont understand question quite clearly,,does permutations of designs matter ?
what do you mean permutation of design?
|dw:1349443924183:dw| |dw:1349443965104:dw|
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