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Mathematics 8 Online
OpenStudy (lgbasallote):

A contractor wishes to build 9 houses, each different in design. In how many ways can he place the houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side?

OpenStudy (anonymous):

Its combination i think...@lgbasallote

OpenStudy (anonymous):

Nope it is purmutation since it is about arrengement.

OpenStudy (anonymous):

he is choosing a slot

OpenStudy (anonymous):

Do u have the answer @lgbasallote

OpenStudy (anonymous):

9!

OpenStudy (anonymous):

The fact you can have facing sides doesn't really make a difference...

OpenStudy (lgbasallote):

i don't @Yahoo!

OpenStudy (anonymous):

I think it is about cyclic purmutation Thus the answer will be (n-1)! =8!

OpenStudy (lgbasallote):

it's cyclic?

OpenStudy (anonymous):

Cyclic means arranging in circular order.

OpenStudy (anonymous):

Why would it be cyclic?

OpenStudy (anonymous):

|dw:1349441737492:dw|

OpenStudy (anonymous):

Which is the same as |dw:1349441806156:dw| Isn't it?

OpenStudy (anonymous):

Which makes it a trivial question really...

OpenStudy (anonymous):

I don't agree why u put the lines together?

OpenStudy (anonymous):

Why not?

OpenStudy (anonymous):

U must have good reason to put them together.

OpenStudy (anonymous):

For the first house you have 9 choices, for the second one 8, for the third one 7 etc. Comes down to 9*8*7*6*5*4*3*2*1 = 9!

OpenStudy (anonymous):

Here is my way, we can consider the road as the center of the circular arrangement so as to apply cyclic permutation.

OpenStudy (anonymous):

|dw:1349442294573:dw|

OpenStudy (anonymous):

Which still gives me 9*8*7*6*5*4*3*2*1 choices

OpenStudy (anonymous):

It will not. For cyclic permutation the formula is (n-1)!

OpenStudy (anonymous):

Slap me around with formulas all you want, i fail to see how 1. The question asks for cyclic permutations 2. (n-1) applies to my drawing...

OpenStudy (anonymous):

Besides, i outrank you 65 > 62 ;)

OpenStudy (shubhamsrg):

9C6 ?

OpenStudy (shubhamsrg):

= 84 ?

OpenStudy (lgbasallote):

is "place" a combination or permutation?

OpenStudy (anonymous):

Since the houses have no relations, it's permutation

OpenStudy (shubhamsrg):

i guess the order in which houses are kept dont matter,,i.e. if 3,7,8 are on one side,,then 3,7,8 ; 3,8,7 ; 8,7,3 etc are the same,,so i say combination..

OpenStudy (shubhamsrg):

ohh wait,,is question like this : 9 houses are there,,6 on 1 side,,3 on other,,and how many different ways can be there to give them 9 different designs ?

OpenStudy (shubhamsrg):

do you have an answer ?

OpenStudy (lgbasallote):

i do not

OpenStudy (shubhamsrg):

hmm,,maybe i dont understand question quite clearly,,does permutations of designs matter ?

OpenStudy (lgbasallote):

what do you mean permutation of design?

OpenStudy (shubhamsrg):

|dw:1349443924183:dw| |dw:1349443965104:dw|

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