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Integrate :
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\[\int\limits_{}^{} \frac{ x }{ \sqrt{4+x ^{2}} }dx=\]
put x^2+4=u
Ok so i substitute it, What next ??
\[x=\sqrt{u-4}\]
dx= ?
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ohh i should derivate it
lol. no , don't try to find x....
differentiate this : x^2+4=u
dx=du/2x
that is xdx = du/2 ok?
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Yeah right
so u get int of 1/ root u du/2 right ?
\[\int\limits_{}^{}\frac{ du }{ \sqrt{u} 2}\]
yup, so 1/root u = u^{what} ?
u^-1/2
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can u integrate that?
2u^1/2
isn't it just root u ?
yeah If we cancel it Only root u is left what next ??
resubstitute u = ....
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add +c in the end
\[\sqrt{4+x ^{2}}+c\]
that is correct.
Thankyou very Much :)
welcome ^_^
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