Integrate :
\[\int\limits_{}^{}xe ^{x}dx=\]
go for by parts..
i dont know integration by parts
or u can use \(\int e^x(f(x)+f'(x))dx=e^xf(x)+c\)
@hartnn Can You Show Me How to Do This Because I am Confused ?
f(x)=x-1
use by parts integration by parts is \[\Large \int\limits_{}^{}udv=vu-\int\limits_{}^{}vdu\] here dv=e^x so v=e^x u=x so du =1
or you may try logically,, see,, d/dx(x e^x) = xe^x + e^x =>d(x e^x) = (x e^x)dx + e^x dx now integrate both sides.. =>xe^x = integral(x e^x) + e^x you may now solve for integral (x e^x) dx .. hope it helps..
\(\large \int e^xxdx=\int e^x(x-1+1)dx=e^x(x-1)+c\)
i missed a constant in the end,,make that correction..
note derivative of x-1 is 1
Can you guys show Integration by parts ??
sami showed it nicely, which part did u not understand ?
Actually i was telling to use it to solve this question
so now could u do it by yourself? with the procedure given by sami ?
No leave it @hartnn I got it Thanks Alot Everyone :)
intergration by parts will be very useful.......
I know But I never concentrated bcz i had jaundice when integration was being taught in college :(
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