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Chemistry 10 Online
OpenStudy (anonymous):

Identify the atomic numbers of elements with the following electron configurations: a. 1s2 2s2 2p2 b. 1s2 2s2 2p6 3s2 3p1 c. 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d10

OpenStudy (aaronq):

are these neural atoms?

OpenStudy (aaronq):

neutral*

OpenStudy (anonymous):

As far as I am aware, yes.

OpenStudy (aaronq):

so count the number of electrons present, this number will equal the number of protons (since it's neutral), and therefore corresponds to the atomic number which gives you the identity of the element in question.

OpenStudy (anonymous):

So it'd be Carbon, Aluminum,, and Silver, right?

OpenStudy (aaronq):

exactly

OpenStudy (anonymous):

Wow, I was making that way harder than I needed to. Thank you!

OpenStudy (aaronq):

no prob, now you know how to it (y)

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