Find size of angle ABC
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Then find length of AD
I used cosine rule: b^2=a^2 + c^2 - 2ac cosB 11.4^2 = 5.7^2 + 7.6^2 -(2*5.7*7.6*cosB) 129.96-32.49-57.76 = -86.64*cosB cosB = -(39.71/86.64) B = 117.28
Then used sine rule to find angle A as 63.62
No, sorry, A = 26.38
Therefore angle ACD = 90 - 26.38 = 63.62
So using sine rule, sin CAD/CD = sin D/AC sin 63.62/CD = sin 90/11.4 CD sin 90 = 11.4 sin 63.62 CD = 11.4 sin 63.62/sin 90 CD = 10.2
Could someone check this is correct? Thanks so much :-)
Angle ACD in step 5 should read angle CAD
if u have got angle a...u can use SOH CAH TOA..u will get length AD
Oh, that's much easier! So angle A = 26.58, hypotenuse is 11.4, and AD is adjacent, so cos26.58 = AD/11.4 AD = 11.4 cos 26.58 AD = 10.2 Thanks, I didn't spot that
But other than that, do you agree with my answer?
yepz u amswer is completely right...bu to save time for exams,u can use my method
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