If AB, then A∩B = AB. Always Sometimes Never Which one?
Incomplete!
If AB what?
its supposed to bb A sidways u and B
\(A \cap B=A \subseteq B\)
Oh,\[\rm A\subset B\]A is a subset of B.
@swissgirl yup thats how it looks how u type that?
if \(A\subset B\) then \(A\cap B\)=A
\ (A\cap B=A \subseteq B\ ) If you remove the spaces btwn \ and ( then It will appear
An example: Let's define A as {1,2,3} and B as {1,2,3,4,5......}. Then, \(\rm A\cap B = \{1,2,3\} = A\)
\(A \cap B\) means the intersection of A and B Meaning the elements that both A and B have Lets draw a diagram |dw:1349451197948:dw| The shaded region is the intersection of A and B
You could say that a new set \(\rm A \cap B\) consists of the common elements in \(\rm A\) and \(\rm B\).
If \(A \subseteq B\), then A∩B = \(A \subseteq B\). Always Sometimes Never Which one? Is this the question?
So \(A \subseteq B\) Means that everything in A is everything in B Meaning A is contained in B |dw:1349451437835:dw|
Now we can see that the intersection of A and B is A |dw:1349451524372:dw| The whole circle A is the intersection of A and B \( A \cap B \)
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