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Mathematics 7 Online
OpenStudy (anonymous):

What is the solution of the system of equations?

OpenStudy (anonymous):

OpenStudy (cwrw238):

subtracting equation 1 from equation 3 gives 2z = -6 so z = -3 plug this value into equations 1 and 2 will give 2 equations in x and y

OpenStudy (cwrw238):

can you continue from there?

OpenStudy (anonymous):

@Chlorophyll

OpenStudy (anonymous):

@sue101 I'd follow exactly @cwrw238 instruction: Now start with subtract equa. (3) \ (1)

OpenStudy (anonymous):

So the point of this problem is that I have to find out what is x y and z right?

OpenStudy (anonymous):

Yes, find out the values of whatever variables :)

OpenStudy (anonymous):

Alright I think I can do this. I will first do it on a piece of paper then I will type it up on here. Then you see if I am correct. ;) thx

OpenStudy (anonymous):

Okie :)

OpenStudy (anonymous):

@Chlorophyll

OpenStudy (anonymous):

Could you show your work here?

OpenStudy (anonymous):

I just add all the x's the y's and the z's... I probably did do it wrong:(

OpenStudy (anonymous):

3x + 2y + z = 7 ( 1) 3x + 2y +3z = 1 ( 3) Subtract them:

OpenStudy (anonymous):

ok x + y + 62z

OpenStudy (anonymous):

Subtract them vertically: 3x - 3x = 0. 2y - ....?

OpenStudy (anonymous):

2y - 2y = 0 z - 3z = -2z

OpenStudy (anonymous):

Then 7 - 1 = ...?

OpenStudy (anonymous):

-> - 2z = ...?

OpenStudy (anonymous):

6

OpenStudy (anonymous):

=> z = ....?

OpenStudy (anonymous):

i dnt understand ur question :(

OpenStudy (anonymous):

Do you understand until this part: - 2z = 6 ?

OpenStudy (anonymous):

yes now i have to divide both sides bt -2 to get z alone nd i get -3

OpenStudy (anonymous):

That's how cwrw238 wants you to do :)

OpenStudy (anonymous):

ah I see so now I plug in -3 for z in the first and second equation. 3x +2y + -3 = 7 - 5x + 5y + 4(=3)

OpenStudy (anonymous):

The next step is plug z = -3 into equa. (1) and (2) :

OpenStudy (anonymous):

3x + 2y = ...? 5x + 5y = ...?

OpenStudy (anonymous):

3x + 5x = 8x 2y + 5y = 7y

OpenStudy (anonymous):

3x +2y + -3 = 7 5x + 5y + 4(-3) = 3

OpenStudy (anonymous):

-> 3x + 2y = 10 -> 5x + 5y = ...

OpenStudy (anonymous):

8x + 7y = 10

OpenStudy (anonymous):

Just fill in where the dot is: 5x + 5y + 4(-3) = 3 -> 5x + 5y = ...?

OpenStudy (anonymous):

7?

OpenStudy (anonymous):

5x + 5y + 4(-3) = 3 -> 5x + 5y = 3 + 12 = ...?

OpenStudy (anonymous):

15

OpenStudy (anonymous):

> 3x + 2y = 10 -> 5x + 5y = 15 or x + y = 3

OpenStudy (anonymous):

Now solve for x and y, can you?

OpenStudy (anonymous):

ok do I subtract both of these??

OpenStudy (anonymous):

x + y = 3 (1) 3x + 2y = 10 (2) Multiply the first for 2, then subtract

OpenStudy (anonymous):

I am soooo lost with this problem im just doing what you are telling me to do but I have no IDEA WHAT IM DOING IM SO FRUSTRATED!!

OpenStudy (anonymous):

Read cwrw238 fist post, which is the guide line!

OpenStudy (anonymous):

I think i might just pass the question, why do they have to work my brain soo hard for just 2 points!!

OpenStudy (anonymous):

You need to relearn and keep practicing of solving the system of equation by elimination or substitution.

OpenStudy (anonymous):

This type of solving is foundation of basic algebra. If you don't need algebra so just skip it for the rest of your life :)

OpenStudy (anonymous):

I was going to but the teacher stopped me from doing so XD

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