What is the solution of the system of equations?
subtracting equation 1 from equation 3 gives 2z = -6 so z = -3 plug this value into equations 1 and 2 will give 2 equations in x and y
can you continue from there?
@Chlorophyll
@sue101 I'd follow exactly @cwrw238 instruction: Now start with subtract equa. (3) \ (1)
So the point of this problem is that I have to find out what is x y and z right?
Yes, find out the values of whatever variables :)
Alright I think I can do this. I will first do it on a piece of paper then I will type it up on here. Then you see if I am correct. ;) thx
Okie :)
@Chlorophyll
Could you show your work here?
I just add all the x's the y's and the z's... I probably did do it wrong:(
3x + 2y + z = 7 ( 1) 3x + 2y +3z = 1 ( 3) Subtract them:
ok x + y + 62z
Subtract them vertically: 3x - 3x = 0. 2y - ....?
2y - 2y = 0 z - 3z = -2z
Then 7 - 1 = ...?
-> - 2z = ...?
6
=> z = ....?
i dnt understand ur question :(
Do you understand until this part: - 2z = 6 ?
yes now i have to divide both sides bt -2 to get z alone nd i get -3
That's how cwrw238 wants you to do :)
ah I see so now I plug in -3 for z in the first and second equation. 3x +2y + -3 = 7 - 5x + 5y + 4(=3)
The next step is plug z = -3 into equa. (1) and (2) :
3x + 2y = ...? 5x + 5y = ...?
3x + 5x = 8x 2y + 5y = 7y
3x +2y + -3 = 7 5x + 5y + 4(-3) = 3
-> 3x + 2y = 10 -> 5x + 5y = ...
8x + 7y = 10
Just fill in where the dot is: 5x + 5y + 4(-3) = 3 -> 5x + 5y = ...?
7?
5x + 5y + 4(-3) = 3 -> 5x + 5y = 3 + 12 = ...?
15
> 3x + 2y = 10 -> 5x + 5y = 15 or x + y = 3
Now solve for x and y, can you?
ok do I subtract both of these??
x + y = 3 (1) 3x + 2y = 10 (2) Multiply the first for 2, then subtract
I am soooo lost with this problem im just doing what you are telling me to do but I have no IDEA WHAT IM DOING IM SO FRUSTRATED!!
Read cwrw238 fist post, which is the guide line!
I think i might just pass the question, why do they have to work my brain soo hard for just 2 points!!
You need to relearn and keep practicing of solving the system of equation by elimination or substitution.
This type of solving is foundation of basic algebra. If you don't need algebra so just skip it for the rest of your life :)
I was going to but the teacher stopped me from doing so XD
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