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Mathematics 19 Online
OpenStudy (anonymous):

Find the derivative of f(x) using the definition of a derivative.

OpenStudy (anonymous):

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OpenStudy (anonymous):

using limit formula ? or by standard derivatives ?

OpenStudy (anonymous):

Limit formula.

OpenStudy (anonymous):

a weeks worth of algebra, and a rather sadistic question

OpenStudy (anonymous):

No kidding!!!

OpenStudy (anonymous):

\[f'(x) = \frac{f(x+\Delta{x})-f(x)}{\Delta{x}}\]

OpenStudy (anonymous):

well not so bad if you start with \[\frac{1}{\sqrt{x}}+x^2\]

OpenStudy (anonymous):

I know that lol. But I cannot get rid of the h's. I got lost on simplyfing this monster,

OpenStudy (anonymous):

and since the limit of the sum is the sum of the limits, you can do this in pieces

OpenStudy (anonymous):

I have to do it as a single definition.

OpenStudy (anonymous):

so.....

OpenStudy (anonymous):

hahaha...

OpenStudy (anonymous):

for example, the second one is standard and rather simple \[\lim_{h\to 0}\frac{(x+h)^2-x^2}{h}=\lim_{x\to 0}\frac{x^2+2xh+h^2-x^2}{h}\]\[-\lim-{h\to 0}\frac{2xh+h^2}{h}=\lim_{x\to 0}2x+h=2x\] easy one

OpenStudy (anonymous):

I get that but I have to use a single definition. No combining functions allowed.

OpenStudy (anonymous):

I mean no seperating allowed.

OpenStudy (anonymous):

\[\lim_{h\to 0}\frac{\frac{1}{\sqrt{x+h}}-\frac{1}{\sqrt{x}}}{h}\] might be harder, but not much

OpenStudy (anonymous):

why there is a rule for not separating ??

OpenStudy (anonymous):

Professor said so.

OpenStudy (anonymous):

no matter, write it as one thing, then group them as first one as second one the limit of the sum is the sum of the limits, it is the commutative law after all

OpenStudy (anonymous):

so you can write it as one long piece if you like, but you will still combine like terms and get the same thing it makes no difference, just looks messier

OpenStudy (anonymous):

Hmm... good point.

OpenStudy (anonymous):

Thanks! Makes this monster a lot easier to derive.

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