Question

Ben uses a compass and a straightedge to construct angle DEF is congruent to angle ABC, as shown

Answer 1

Uh huh, and then what?

Answer 2

Lol,

Which statement best explains why Ben uses the width BI to create the arc JK from point E?

angle DEF is congruent to angle ABC when BH = EK, BI = JK, and HI = EJ.

BI = JK when angle DEF is congruent to angle ABC.

BI = EJ when angle DEF is congruent to angle ABC.

angle DEF is congruent to angle ABC when BH = EJ, BI = EK, and HI = JK.

Answer 3

@CliffSedge

Answer 4

Compare each of those statements to the picture and see if you can find which ones don't make sense.

Answer 5

Think of it in terms of proving two triangles congruent by side-side-side theorem.

Answer 6

Im still having problems. All this is what confuses me!

Answer 7

Think about drawing that first arc around ABC; it makes BI=BH. (postulate I.3.)
By copying those lengths (prop. I.2.) over to DEF; it makes BI=BH=EK=EJ.
That gives two pairs of congruent sides.
Lastly, copying HI to JK, that provides the third pair of congruent sides and you'll have two triangles congruent by SSS. (prop. I.8.)
You can then deduce that the angles are equal because of CPCTC (corresponding parts of congruent triangles are congruent).