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Mathematics 22 Online
OpenStudy (anonymous):

Help? Question attached--graphing and finding domain. Need a mathematical explanation step by step. :)

OpenStudy (anonymous):

hey.. two options : if you know how the graph of x^(1/2) looks like it will be the same just negative and shifted to the left by one unit

OpenStudy (anonymous):

second method : plug different values for x and you will get f(x) then draw those points on

OpenStudy (anonymous):

each method will give you the graph eventually.. the first one will be easier but we can do the two of them so you will learn

OpenStudy (anonymous):

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OpenStudy (anonymous):

this is the graph of x^(1/2) the graph of - (x+1)^(1/2) will be the negative of this graph (like putting a mirror along the x axis .. you see a mirror image) and if will be shifted one unit to the left since you have x+1

OpenStudy (anonymous):

i say easy - you might prefer the other method .. the other method is just plugging values of x for example x = 0 gives you y = -1 x = 3 y = -2 x = -1 y = 0 mark those points on your paper and then connect them with a curve

OpenStudy (anonymous):

yes.. you take some values for x and get the corresponding values of f(x) then you have dots with coordinates (x,f(x))

OpenStudy (anonymous):

ok lets choose x = 0 plug it into f(x) so : f(0) = - (0+1)^(1/2) = - (1)^(1/2) = -1 so we have the point (0,-1) lets choose x = 3 plug it into f(x) so : f(3) = -(3+1)^(1/2) = - (4)^(1/2) = -2 take for example x = -1 what do you get ?

OpenStudy (anonymous):

no, f(-1) = - (-1+1)^(1/2) = 0

OpenStudy (anonymous):

so you have the points : (0,-1) , (3,-2) , (-1,0)

OpenStudy (anonymous):

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