A company's revenue (in dollars) can be modeled by the function R (p) = -15p^2 + 200p +10,000 where p is the price in dollars of the company's product. What price (in dollars) will maximize the revenue? Round to the nearest penny.
Differentiate and put equal to 0 for max
Clarify what you mean by that...
Differentiate R(p) with respect to p and put the resulting equal to 0 in order to calculate the value of p for which R(p) is a maximum.
Yeah you completely lost me, aha. This is High School Math that how now been brought to another lane of confusion. I know I have to follow -b/2a... I will try to refer to another source for some help.
It's a quadratic equation, the graph of which is a parabola. Find the vertex of the parabola.
That in fact amounts to exactly the same thing Diff ax^2 +bx +c = 2ax + b = 0 -> x = -b/2a
Of course it does, estudier, but if 1missmanhattan doesn't know calculus . . .
-b/(2a) will work. Use b=200, a =-15
Never too early to start:-)
It's too early if the student doesn't have the requisite fundamentals. I saw a little earlier someone with a calculus question who struggled to find the area of a rectangle. It's a nice taste of things to come, though to let 1miss know that -b/2a can be found from the first derivative, but it might be better right now to relate it to something more familiar like the quadratic formula.
Agreed, go ahead....
Well, I think our student has already jumped ship.
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