Ask your own question, for FREE!
Physics 18 Online
OpenStudy (anonymous):

Conservation of Mechanical Energy: A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is the initial height of the bob?

OpenStudy (anonymous):

|dw:1349481173829:dw|

OpenStudy (anonymous):

Why would K(A) be 0?

OpenStudy (anonymous):

Yes, it 'released' without initial speed right?

OpenStudy (anonymous):

isnt the initial speed 1.9 m/s?

OpenStudy (anonymous):

No, that's the speed at B.

OpenStudy (anonymous):

oh ok so you got the zero from A?

OpenStudy (anonymous):

Yup :)

OpenStudy (anonymous):

but the book says tha answer is 0.18m but how would you get that answer?

OpenStudy (anonymous):

*the

OpenStudy (anonymous):

I got the same answer. I wrote the formula at the picture:\[h=\frac{v^2}{2g}\]

OpenStudy (anonymous):

when it comes to a pendulum does it not depend on the lenght of the string?

OpenStudy (anonymous):

U=mgl

OpenStudy (anonymous):

ok, so you would use that formula, h=v^2/2g to get 0.18m?

OpenStudy (anonymous):

@Jasminebunnies : Yes

OpenStudy (anonymous):

ohhh ok and the zero is put there because there is no mass?

OpenStudy (anonymous):

Omg! (^ ^!) Which zero?

OpenStudy (anonymous):

lol! the zero in your original equation that you said came from A, in front of mgh

OpenStudy (anonymous):

That's because v=0 at highest point.

OpenStudy (anonymous):

ohhh ok, is that because it has not been released at that point?

OpenStudy (anonymous):

@imron07

OpenStudy (anonymous):

Because by the time the pendulum is released, the velocity is zero. It start from rest.

OpenStudy (anonymous):

yes, ok! thank you! I understand now :)

OpenStudy (anonymous):

ok ;)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!