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Mathematics 12 Online
OpenStudy (anonymous):

Decide if the function shown in the figure below is a probability density function (pdf) or a cumulative distribution function (cdf). Let A = 4. This function is a cumulative distribution function or probability density function? PLease explain to me why Find the exact value of c. Please explain how you found c. Attachement below

OpenStudy (anonymous):

OpenStudy (anonymous):

I need a calc genius!!

OpenStudy (anonymous):

It's continuing to increase up to some maximum value, so it looks like probabilities are accumulating. For either cdf or pdf, the area under the curve =1, so you can use that and the geometry of the graph to find Ac and c.

OpenStudy (anonymous):

I hope I'm interpreting this right. . .

OpenStudy (anonymous):

How did you determine that the area was 1. And how geometrically

OpenStudy (anonymous):

Sorry. Correction, for a cumulative function, the maximum value is 1. This means that A∙c=1, and since A=4, c=1/4.

OpenStudy (anonymous):

I guess im still confused. How can it be both a cdp and pdf?

OpenStudy (anonymous):

It is not both. It is cpd

OpenStudy (anonymous):

If pdf then the area under the curve =1, but this is cumulative so the max. value =1.

OpenStudy (anonymous):

ah. How did you determine it was a cdf? Sorry pleas bare with me

OpenStudy (anonymous):

From the shape of it. The probabilities are increasing as it goes and maxes out in a flat line that continues indefinitely. If it were a pdf, then at some point, the curve would have to come back down to zero.

OpenStudy (anonymous):

oh my mistaske got it! thank you very much wish you were my calc teacher

OpenStudy (anonymous):

If you have more probability/stats-like questions, try this site. It is very easy to read: http://stattrek.com/probability-distributions/probability-distribution.aspx?Tutorial=Stat

OpenStudy (anonymous):

Thanks cliffsedge

OpenStudy (anonymous):

You're welcome.

OpenStudy (anonymous):

Oh, for cdf what would c be? (Its regarding another problem)- Does its also tend to 1?

OpenStudy (anonymous):

I now know its pdf(thanks to you)

OpenStudy (anonymous):

got it :)

OpenStudy (anonymous):

Is A still 4 in this case?

OpenStudy (anonymous):

I got it ;) it was 3. Im i right in the fact that i set the area under the curve to that of a triangle egual to 1?

OpenStudy (anonymous):

Yes, if A=3, then area = 1= 0.5(3)(c).

OpenStudy (anonymous):

cool whip

OpenStudy (anonymous):

Indeed. \[\large \ddot \smile\]

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