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Chemistry
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Calculate the enthalpy for the following reaction: N2 + O2 → 2 NO given the following bond dissociation energies: N2 = 226 kcal/mol, O2 = 199 kcal/mol and NO = 145 kcal/mol.
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ok so for NO to form you need to break N2 and O2 bonds which is endothermic process and then forming of NO is exothermic so it goes like this: 226 + 199 - (2 * 145) = ??? positive values are for endothermic processes and negative for exothermic... got it?
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