Question

help plz

Answer 1

shoot

Answer 2

1st question
\[2logx- \log(x+6)= 3\log2\]

Answer 3

2nd question..
\[4\log_{2} (x^{2} + 1 ) = \log_{2} 625\]

Answer 4

\[4\log_{2} (x^2+1) = \log_{2} (x^2+1)^4\]

Answer 5

\[\log_{2} 625 = \log_{2} 5^4\]

Answer 6

I think nw u can solve this by equating..)

Answer 7

1st can be written as
\[\Large \log x^2-\log(x+6)=\log 2^3\]
or
\[\Large \log (\frac{x^2}{x+6})=\log 8\]
\[\Large \implies \frac{x^2}{x+6}=8\]
i hope now you can solve this using Quadratic equation
\[\Large \implies x^2-8x-48=0\]

Answer 8

3rd question
\[\left(\begin{matrix}\log (x ^{2} + y ) - \log (x-2y) = 1 \\ 5^{x+1} = 25^{y+1}\end{matrix}\right)\]

Answer 9

\[(x^2+1)^4 = 5^4\]

\[x^2+1=5\]
\[x^2 = 4\]
\[x=\pm2\]

Answer 10

Did u understand @Muskan

Answer 11

yess

Answer 12

question 4..
\[\frac{ 1 }{ x } + \frac{ 1 }{ y } = 1 - \frac{ 1 }{ xy }\]
\[xy=6\]

Answer 13

Lol...u r trying to hit 4 mangoes with one stone...)

Answer 14

yes..

Answer 15

Agaimst COD....

Answer 16

i have no time for do these questions..

Answer 17

question 5
Gauss
5x−4y+3z=9

2x+y−2y=1

4x+3y+4z=1